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基本数据类型重点作业
阅读量:5046 次
发布时间:2019-06-12

本文共 29154 字,大约阅读时间需要 97 分钟。

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#实现用户输入用户名和密码,当用户名为 seven 或 alex 且 密码为 123 时,显示登陆成功,否则登陆失败,失败时允许重复输入三次s = 3while s>0:    name = input("请输入用户名:").strip()    password = input("请输入密码:").strip()    if name == "seven" or name == "alex" and password =="123":        print("登录成功")        break    else:        print("登录失败,你还有%s次机会" %s)        s -= 1
#使用 while 循环实现输出 2 -3 + 4-5 + 6 ... + 100的和sum = 0a = 2while a<=100:    if a%2==0:        sum += a    else:        sum -= a    a += 1print(sum)
#使用 for 循环和 range 实现输的1 -2 + 3-4 + 5-6 ... + 99的和sum = 0for i in range(100):    if i % 2 == 0:        sum -= i    else:        sum += iprint(sum)
#使用 while 循环实现输出  1,2,3,4,5,7,8,9,11,12a = 1while a<13:    print(a)    a += 1
#使用 while 循环实现输出 1-100 内的所有奇数a = 1while a <= 100:    if a % 2 == 0:        pass    else:        print(a)    a += 1
#分别书写数字 5,10,32,7 的二进制表示for i in [5,10,32,7]:    print("{}的二进制数是{}".format(i,bin(i)))    print("%s的二进制数是%s" %(i, bin(i)))
#输入一年份,判断该年份是否是闰年并输出结果。(编程题)#注:凡符合下面两个条件之一的年份是闰年。 (1) 能被4整除但不能被100整除。 (2) 能被400整除。year = input("请输入您需要查询的年份:").strip()year = int(year)if year % 4 == 0 and year % 100 != 0 or year % 400 ==0:    print("%d是闰年" %year)
#编写登陆接口# 基础需求:# 让用户输入用户名密码# 认证成功后显示欢迎信息# 输错三次后退出程序count = 3while count > 0:    name = input("帐号:")    password = input("密码:")    if name == "long" and password == "123":        print("欢迎登录")        break    else:        count -= 1        print("登录失败,你还有%d次机会" %count)
#如有一个变量n1 = 5,请使用int提供的方法,得到该变量最少可以用多少个二进制位表示?n1 = 5print(int.bit_length(n1))
#判断name变量对应的值是否以"al"开头,并输出结果name=" aleX"print(name.startswith("al"))
#将name变量对应的值中的"l"替换为"p",并输出结果name=" aleX"print(name.replace("l","p"))
#请输出name变量对应的值的后2个字符?name=" aleX"print(name[-2:])  #-1代表最后一个字符,-2代表倒数第二个字符
#获取子序列,仅不包含最后一个字符。如:oldboy 则获取oldbo;root则获取rooname=" aleX"print(name.rstrip(name[-1:]))
#利用下划线将列表的每一个元素拼接成字符串,li = "alexericrain"li = "alexericrain"print("_".join(li))
#计算用户输入的内容中有几个十进制数?几个字母?#如:#content=input('请输入内容:') #如: asduiaf878123jkjsfd-213928content = input('请输入内容:') .strip()  #一定要记得使用strip去除空格v,r = content.split("+")print(int(v)+int(r))
#计算用户输入的内容中有几个十进制数?几个字母?# 如:# content=input('请输入内容:') #如: asduiaf878123jkjsfd-213928content=input('请输入内容:').strip()v = 0s = 0for i in content:    if i.isdecimal():        v += 1    if i.isalpha():        s += 1    else:        passprint("数字的个数是%d,字母的个数是%d" %(v,s))
while True:    name = input("请输入用户名:")    if name == "q" or name == "Q":        break    if len(name) <= 20:        pass    else:        name = name[:20]    password = input("请输入密码:")    if password == "q" or password == "Q":        break    if len(password) <= 20:        pass    else:        password = password[:20]    email = input("请输入邮箱:")    if email == "q" or email == "Q":        break    if len(email) <= 20:        pass    else:        email = email[:20]    template = "{0}\t{1}\t{2}\n"    v = template.format(name,password,email)    breakprint(v.expandtabs(20))  #将\t以及\n转化为空格或者回车
#往names列表里black_girl前面插入一个alexnames = ["old_driver","rain","jack","shanshan","peiqi","black_girl"]names.insert(names.index("black_girl"),"alex") #占有原来的位置print(names)
#把shanshan的名字改成中文,姗姗names = ["old_driver","rain","jack","shanshan","peiqi","black_girl"]names[names.index("shanshan")] = "姗姗"print(names)
#往names列表里rain的后面插入一个子列表,["oldboy","oldgirl"]names = ["old_driver","rain","jack","shanshan","peiqi","black_girl"]names.insert(names.index("rain")+1,["oldboy","oldgirl"])print(names)
#创建新列表[1,2,3,4,2,5,6,2],合并入names列表names = ["old_driver","rain","jack","shanshan","peiqi","black_girl"]names.extend([1,2,3,4,5,6,2])print(names)
#.取出names列表中索引2-10的元素,步长为2names = ["old_driver","rain","jack","shanshan","peiqi","black_girl"]print(names[2:10:2])
#循环names列表,打印每个元素的索引值,和元素names = ["old_driver","rain","jack","shanshan","peiqi","black_girl"]for index,name in enumerate(names):    print("%s,%s" %(index,name))
#循环names列表,打印每个元素的索引值,和元素,当索引值为偶数时,把对应的元素改为-1names = ["old_driver","rain","jack","shanshan","peiqi","black_girl"]for index,name in enumerate(names):    if index % 2 == 0:        name = "-1"    else:        pass    print(index,name)
#这一题没理解 #names里有3个2,请返回第2个2的索引值。不要人肉数,要动态找(提示,找到第一个2的位置,在次基础上再找第2个)print(names.index(2,names.index(2)+1))

 

#查找列表(或元祖或字典)中元素,移除每个元素的空格,并查找以 a 或 A 开头 并且以 c 结尾的所有元素# li = ["alec", " aric", "Alex", "Tony", "rain"]# tu = ("alec", " aric", "Alex", "Tony", "rain")# dic = {'k1': "alex", 'k2': ' aric',"k3": "Alex", "k4": "Tony"}li = ["alec", " aric", "Alex", "Tony", "rain"]for i in li:    i = i.strip()    c_a = i.startswith("a")    c_A = i.startswith("A")    c_c = i.endswith("d")    if c_a or c_A and c_c:        print(i)tu = ("alec", " aric", "Alex", "Tony", "rain")for i in tu:    i = i.strip()    c_a = i.startswith("a")    c_A = i.startswith("A")    c_c = i.endswith("d")    if c_a or c_A and c_c:        print(i)dic = {
'k1': "alex", 'k2': ' aric',"k3": "Alex", "k4": "Tony"}for i in dic: i = i.strip() c_a = i.startswith("a") c_A = i.startswith("A") c_c = i.endswith("d") if c_a or c_A and c_c: print(i)
#列表中追加元素 “seven”,并输出添加后的列表li = ['alex','eric','rain']li.append("seven")print(li)
#请在列表的第 1 个位置插入元素 “Tony”,并输出添加后的列表 li = ['alex','eric','rain']li.insert(0,"Tony")  #append是追加 insert是在指定位置添加print(li)
# 写代码,有如下字典,按照要求实现每一个功能,dic = {'k1':'v1','k2':'v2','k3':[11,22,33]}# 请循环输出所有的 keydic = {
'k1':'v1','k2':'v2','k3':[11,22,33]}for i in dic.keys(): print(i)
# 请循环输出所有的 key 和 valuedic = {
'k1':'v1','k2':'v2','k3':[11,22,33]}for i in dic.keys(): print(i,dic[i])
# 请在字典中添加一个键值对,'k4':'v4',输出添加后的字典dic = {
'k1':'v1','k2':'v2','k3':[11,22,33]}dic['k4'] = 'v4' #通过索引添加print(dic)dic = {
'k1':'v1','k2':'v2','k3':[11,22,33]}dic.update({
'k4':'v4'}) # 传一个字典print(dic)dic = {
'k1':'v1','k2':'v2','k3':[11,22,33]}dic.update(k4 = "v4") # 传关键字print(dic)dic = {
'k1':'v1','k2':'v2','k3':[11,22,33]}dic.update(zip(['k4'],['v4'])) # 传一个zip函数print(dic)dic = {
'k1':'v1','k2':'v2','k3':[11,22,33]}dic.update([('k4','v4')]) # 传一个包含一个或多个元祖的列表print(dic)
# 请在k3对应的值中追加一个元素44,输出修改后的字典dic = {
'k1':'v1','k2':'v2','k3':[11,22,33]}dic["k3"].append("44")print(dic)
# 请在k3对应的值的第1个位置插入个元素18,输出修改后的字典dic = {
'k1':'v1','k2':'v2','k3':[11,22,33]}dic["k3"].insert(0,18)print(dic)
#请删除字典中键值对,'k1':'v1',并输出删除后的字典dic = {
'k1':'v1','k2':'v2','k3':[11,22,33]}dic.pop("k1")print(dic)dic = {
'k1':'v1','k2':'v2','k3':[11,22,33]}del dic['k1']print(dic)
#请删除字典中的键'k5'对应的键值对,如果字典中不存在键'k5',则不报错,并且让其返回 Nonedic = {
'k1':'v1','k2':'v2','k3':[11,22,33]}pop_k5=dic.pop("k5","None")print(pop_k5)
#请获取字典中'k2'对应的值dic = {
'k1':'v1','k2':'v2','k3':[11,22,33]}view_k2=dic["k2"]print(view_k2)dic = {
'k1':'v1','k2':'v2','k3':[11,22,33]}view_k2=dic.get("k2")print(view_k2)
#现有 dic2 = {'k1':'v111','a':'b'}通过一行操作使 dic2 = {'k1':'v1','k2':'v2','k3':'v3','a','b'}dic2 = {
'k1':'v111','a':'b'}dic2.update({
"k1":"v1","k2":"v2","k3":"v3"})print(dic2)
# lis = [['k',['qwe',20,{'k1':['tt',3,'1']},89],'ab']]# 将列表 lis 中的'tt'变成大写(用两种方式)lis = [['k',['qwe',20,{
'k1':['tt',3,'1']},89],'ab']]view_lis_tt = lis[0][1][2]["k1"]view_tt = lis[0][1][2]["k1"][0]view_lis_tt[0] = view_tt.upper()print(lis)
# 将列表中的数字 3 变成 字符串 '100'(用两种方式)lis = [['k',['qwe',20,{
'k1':['tt',3,'1']},89],'ab']]lis[0][1][2]["k1"][1]="100"print(lis)lis = [['k',['qwe',20,{
'k1':['tt',3,'1']},89],'ab']]lis[0][1][2].update({
"k1":["tt","100","1"]})print(lis)
# 将列表li = ["alex", "seven"]转换成字典且字典的key按照10开始向后递增li = ["alex", "seven"]li_dic={}for k,v in enumerate(li,10):    li_dic[k]=vprint(li_dic)
# 有如下值集合[11,22,33,44,55,66,77,88,99,90],将所有大于66的值保存至字典的第一个key中,将小于66的值保存至第二个key的值中。# 即:{'k1':大于66的所有值, 'k2':小于66的所有值}li=[11,22,33,44,55,66,77,88,99,90]li1=[]li2=[]for i in li:    if i>66:        li1.append(i)    if i<66:        li2.append(i)    else:        passdic = {
"k1":li1,"k2":li2}print(dic)

 

# 输出商品列表,用户输入序号,显示用户选中的商品# 商品 li = ["手机", "电脑", '鼠标垫', '游艇']# 允许用户添加商品# 用户输入序号显示内li = ["手机", "电脑", '鼠标垫', '游艇']while True:    print("商品信息如下".center(28,"-"))    for index,goods in enumerate(li,1):        print("%s %s"%(index,goods))    choice=input("是否要添加商品(yes/no):")    if choice == "yes" or choice=="y":        add_goods=input("请输入要添加的商品:")        li.append(add_goods)    if choice == "no" or choice == "n":        break    else:        print("你的输入有误,请重新输入:")        continuewhile True:    choice_goods=input("请输入需要查询的序号,如果是非数字将会不执行")    if choice_goods.isdigit():        choice_goods=int(choice_goods)        if choice_goods>=1 and choice_goods<=len(li):            print(li[choice_goods-1])        else:            print("输入的序号不在范围内")    else:        break
# 有两个列表# l1 = [11,22,33]# l2 = [22,33,44]# 获取内容相同的元素列表l1 = [11,22,33]l2 = [22,33,44]s1=set(l1)s2=set(l2)s3=s1&s2s3=list(s3)print(s3)
# 获取l1和l2中内容都不同的元素l1 = [11, 22, 33]l2 = [22, 33, 44]s1 = set(l1)s2 = set(l2)s3 = s2 ^ s1l3 = list(s3)print(l3)
# 利用For循环和range输出# For循环从小到大输出1 - 100for i in range(1,101):    print(i)
# For循环从大到小输出100 - 1for i in range(100,0,-1):    print(i)
# While循环从小到大输出1 - 100n = 1while n <= 100:    print(n)    n += 1
# 利用for循环和range输出9 * 9# 乘法表for i in range(1, 10):    for j in range(1, i + 1):        print("%d*%d=%2d" % (j, i, i * j), end=" ")  # 每次输出不换行(默认print会换行),第二位数字是固定的,所以最外层循环的i代表第二位    print(" ")  # 当j(第一位数字)遍历一遍时换行
# 判断一个数是否为素数while True:    flag=True    num = input("请输入要查询的数字:")    num = int(num)    if num <2 :        flag=False    else:        for i in (2,num):            if i % num ==0:                flag=False                break    if flag == True:        print("%d是素数" %num)    else:        print("%d不是素数" %num)
# 输出100以内的所有素数li = []for n in range(2,101):    flag = True    for i in range(2,n):        if n % i ==0:            flag = False            break    if flag == True:        li.append(n)print(li)
# 求100以内的素数和s = 0for n in range(2,101):    flag = True    for i in range(2,n):        if n % i == 0:            flag = False            break    if flag == True:        s += nprint(s)
# 将[1,3,2,7,6,23,41,24,33,85,56]从小到大排序(冒泡法)li = [1,3,2,7,6,23,41,24,33,85,56]for i in range(len(li)-1):    if  li[i]>li[i+1]:        li[i],li[i+1]=li[i+1],li[i]print(li)

 

# 需求:# 可依次选择进入各子菜单# 可从任意一层往回退到上一层# 可从任意一层退出程序China = {    '河南省': {        '焦作市': ['武陟', '温县', '博爱'],        '郑州市': ['新郑', '荥阳', '中牟'],        '开封市': ['兰考', '尉氏', '杞县'],    },    '广东省': {        '广州市': ['越秀', '荔湾', '番禺'],        '深圳市': ['福田', '罗湖', '龙岗'],        '东莞市': ['莞城', '南城', '东城'],    },}exit_flag = Falsewhile not exit_flag:    print("     \33[31;1m欢迎来到中国\33[1m   ")    print("\33[31;1m-----------\33[1m")    for provinece in China:        print(provinece)    choice_province=input("请输入要进入的省份 输入q退出程序 输入b返回上一级")    if choice_province == "q":        exit_flag=True    if choice_province == "b":        continue    elif choice_province in China:        while not exit_flag:            for city in choice_province:                print(city)            choice_city=input("请输入要进入的市区 输入q退出程序 输入b返回上一级")            if choice_city == "q":                exit_flag = True            if choice_city == "b":                continue            elif choice_city in China[choice_province]:                while not exit_flag:                    for country in choice_city:                        print(country)                    choice_country = input("请输入要进入的县区 输入q退出程序 输入b返回上一级")                    if choice_country == "q":                        exit_flag = True                    if choice_country == "b":                        continue                    elif choice_country in China[choice_province][choice_city]:                        print("你当前的位置是%s%s%s" %(choice_province,choice_city,choice_country))                        exit_flag = True  #得到结果后记得退出                    else:                        print("您输入的县区有误,请重新输入")                        continue            else:                print("您的输入的市区有误,请重新输入")                continue    else:        print("您的输入的省份有误,请重新输入")        continue

 

# 购物车程序# 功能要求:# 1、启动程序后,输入用户名密码后,让用户输入工资,然后打印商品列表# 2、允许用户根据商品编号购买商品# 3、用户选择商品后,检测余额是否够,够就直接扣款,不够就提醒# 4、可随时退出,退出时,打印已购买商品和余额# 5、在用户使用过程中, 关键输出,如余额,商品已加入购物车等消息,需高亮显示# 扩展需求:# 1、用户下一次登录后,输入用户名密码,直接回到上次的状态,即上次消费的余额什么的还是那些,再次登录可继续购买# 2、允许查询之前的消费记录# 1.0版本goods = [{
"name": "电脑", "price": 1999},{
"name": "鼠标", "price": 10},{
"name": "游艇", "price": 20},{
"name": "美女", "price": 998},]shopping_cars=[]money=0money += int(input("请输入你的工资"))exit_flag = Falsewhile not exit_flag: print("\n---------商品信息---------\n") for index,product in enumerate(goods,1): print("%s %s %s" %(index,product["name"],product["price"])) print("\n--------------------------\n") choice_product = input("请输入要购买的商品序号,输入q则退出:") if choice_product.isdigit(): choice_product=int(choice_product) if choice_product>=1 and choice_product <= len(goods): if money>=goods[choice_product-1]["price"]: money -= goods[choice_product-1]["price"] shopping_cars.append(choice_product) print("\n\33[31;1m%s已加入购物车!\33[1m\n" %goods[choice_product-1]["name"]) else: print("\n\33[31;1m加入购物车失败,工资余额已不足!\33[1m\n" ) else: print("你输入的商品序号有错,请再试一次!") elif choice_product == "q": if len(shopping_cars)>0: print("\n\33[31;1m您当前购物车里的商品有:\33[1m\n") for index,product_cars in enumerate(shopping_cars,1): print("%s %s" %(index,product_cars)) else: print("您的购物车为空") print("\n\33[31;1m您的工资余额为:%s 元\33[1m\n" %money) exit_flag = True else: pass
#!/usr/bin/env python# -*- coding:utf-8 -*-import osimport timedef select_user_info():    # 读取用户信息文件,取出用户名、密码、锁定状态、余额组成一个用户信息字典user_info_dict    with open(user_info_f_name, 'r', encoding='utf-8') as user_info_f:        for line in user_info_f:  # 用户信息字符串            user_info_list = line.strip().split(':')  # 将字符串转换为列表            # print(user_info_list) # 用户信息列表            _username = user_info_list[0].strip()  # 用户名            _password = user_info_list[1].strip()  # 密码            _lock = int(user_info_list[2].strip())  # 锁定状态,int类型(0代表未锁定,1代表锁定)            _money = user_info_list[3].strip()  # 余额            user_info_dict[_username] = {
'password': _password, 'lock': _lock, 'money': _money} # 将列表转换为字典 # print(user_info_dict) # 用户信息字典def update_user_info(): # 修改用户信息后,更新user_info.txt文件内容 with open(user_info_f_temp_name, "w", encoding="utf-8") as user_info_f_temp: for user in user_info_dict: # 将字典转换为列表 user_info_list_new = [user, str(user_info_dict[user]['password']), str(user_info_dict[user]['lock']), str(user_info_dict[user]['money'])] # print(user_info_list_new) # 更新后的用户信息列表 user_info_str = ":".join(user_info_list_new) # 将列表转换为字符串 # print(user_str) # 更新后的用户信息字符串 user_info_f_temp.write(user_info_str + "\n") os.replace(user_info_f_temp_name, user_info_f_name)def product_list(): # 商品列表 print("\n------------商品列表------------\n") # 商品列表 for index, product in enumerate(goods, 1): print("%s.%s %d" % (index, product['name'], product['price'])) print("\n-------------------------------")def select_shopping_history(): # 读取消费记录 with open(shopping_history_f_name, "r", encoding="utf-8") as shopping_history_f: print("\n------------消费记录-----------\n") for line in shopping_history_f: shopping_history_list = line.strip().split('|') # print(shopping_history_list) _username = shopping_history_list[0].strip() _time = shopping_history_list[1].strip() _product = shopping_history_list[2].strip() if username in shopping_history_list: print("用户 {0} {1} 购买了 {2}".format(_username, _time, _product)) else: pass print("\n-------------------------------")def update_shopping_history(): # 更新消费记录 now_time = time.strftime('%Y-%m-%d %H:%M:%S') with open(shopping_history_f_name, "a", encoding="utf-8") as shopping_history_f: shopping_history_f.write("\n%s|%s|%s" % (username, now_time, goods[product_id - 1]['name']))# 商品信息goods = [ {
"name": "电脑", "price": 4000}, {
"name": "鼠标", "price": 200}, {
"name": "游艇", "price": 20000}, {
"name": "美女", "price": 1000}, {
"name": "T恤", "price": 50},]# 菜单栏choice_info = """【商品编号】购买商品【h】消费记录【m】余额查询【q】退出商城-------------------------------"""shopping_carts = [] # 初始购物车为空user_info_dict = {} # 初始化用户信息字典为空user_info_f_name = "user_info.txt" # 用户信息文件名user_info_f_temp_name = "user_info.txt.temp" # 用户信息临时文件名shopping_history_f_name = "shopping_history.txt" # 消费记录exit_flag = Falsecount = 0# 主程序开始select_user_info() # 读取用户信息文件,组成user_info_dict字典while count < 3 and not exit_flag: username = input('\n请输入用户名:') if username not in user_info_dict: count += 1 print("\n用户名错误") elif user_info_dict[username]['lock'] > 0: print("\n用户已被锁定,请联系管理员解锁后重新尝试") break else: while count < 3 and not exit_flag: password = input('\n请输入密码:') if password == user_info_dict[username]['password']: print("\n--------欢迎%s登陆本商城--------" % (username)) if int(user_info_dict[username]['money']) == 0: # money = 0表示是首次登陆的用户 while True: money = input("\n请输入您的工资:") # 工资只能是数字 if money.isdigit(): money = int(money) # print(money) break else: print("\n您的工资只能是数字") continue else: money = int(user_info_dict[username]['money']) print("\n\33[31;1m您上次购物后的余额为:%s 元!\33[1m\n" % (money)) while not exit_flag: product_list() # 打印商品列表 print(choice_info) # 选择信息 product_id = input("请输入您要的操作:") if product_id.isdigit(): product_id = int(product_id) if product_id >= 1 and product_id <= len(goods): if money >= goods[product_id - 1]['price']: money -= goods[product_id - 1]['price'] shopping_carts.append(goods[product_id - 1]['name']) print("\n\33[31;1m%s已购买成功!\33[1m\n" % (goods[product_id - 1]['name'])) update_shopping_history() # 写入消费记录文件 user_info_dict[username]['money'] = money update_user_info() # 更新工资余额到文件 else: print( "\n\33[31;1m抱歉,%s购买失败!工资余额不足!\33[1m\n" % (goods[product_id - 1]['name'])) else: print("商品标号有误,请重新输入") elif product_id == "q": if len(shopping_carts) > 0: print("\n\33[31;1m您本次购买的商品及商品数量如下:\33[1m\n") shopping_carts_delRepeat = list(set(shopping_carts)) # 购物车列表去重 for index, product_carts in enumerate(shopping_carts_delRepeat, 1): print("%s. %s * %d" % ( index, product_carts, shopping_carts.count(product_carts))) # 显示同一商品数量 else: print("\n您本次没有购买东西!") print("\n\33[31;1m您的工资余额为:%s 元!\33[1m\n" % (money)) # user_info_dict[username]['money'] = money # update_user_info() # 更新工资余额到文件 exit_flag = True elif product_id == "h": select_shopping_history() choice_continue = input("\n回到菜单栏(直接按回车):") if choice_continue == 'y' or choice_continue == "Y" or choice_continue == "": continue else: print("\n操作失误,强制退出!") exit_flag = True elif product_id == "m": print("\n\33[31;1m您的工资余额为:%s 元!\33[1m\n" % (money)) # user_info_dict[username]['money'] = money # update_user_info() # 更新工资余额到文件 choice_continue = input("\n回到菜单栏(直接按回车):") if choice_continue == 'y' or choice_continue == "Y" or choice_continue == "": continue else: print("\n操作失误,强制退出!") exit_flag = True else: print("\n输入有误,请重新输入") else: count += 1 print('\n密码错误') continue if count >= 3: # 尝试次数大于等于3时锁定用户 if username == "": print("\n您输入的错误次数过多,且用户为空") elif username not in user_info_dict: print("\n您输入的错误次数过多,且用户 %s 不存在" % username) else: user_info_dict[username]['lock'] += 1 # 修改用户字典(锁定状态设为1) # print(user_info_dict) # 更新后的用户信息字典 update_user_info() # 更新user_info.txt文件内容 print("\n您输入的错误次数过多,%s 已经被锁定" % username)
#!/usr/bin/env python# -*- coding:utf-8 -*-import osimport timedef select_user_info():    # 读取用户信息文件,取出用户名、密码、锁定状态、余额组成一个用户信息字典user_info_dict    with open(user_info_f_name, 'r', encoding='utf-8') as user_info_f:        for line in user_info_f:  # 用户信息字符串            user_info_list = line.strip().split(':')  # 将字符串转换为列表            # print(user_info_list) # 用户信息列表            _username = user_info_list[0].strip()  # 用户名            _password = user_info_list[1].strip()  # 密码            _lock = int(user_info_list[2].strip())  # 锁定状态,int类型(0代表未锁定,1代表锁定)            _money = user_info_list[3].strip()  # 余额            user_info_dict[_username] = {
'password': _password, 'lock': _lock, 'money': _money} # 将列表转换为字典 # print(user_info_dict) # 用户信息字典def update_user_info(): # 修改用户信息后,更新user_info.txt文件内容 with open(user_info_f_temp_name, "w", encoding="utf-8") as user_info_f_temp: for user in user_info_dict: # 将字典转换为列表 user_info_list_new = [user, str(user_info_dict[user]['password']), str(user_info_dict[user]['lock']), str(user_info_dict[user]['money'])] # print(user_info_list_new) # 更新后的用户信息列表 user_info_str = ":".join(user_info_list_new) # 将列表转换为字符串 # print(user_str) # 更新后的用户信息字符串 user_info_f_temp.write(user_info_str + "\n") os.replace(user_info_f_temp_name, user_info_f_name)def product_list(): # 商品列表 print("\n------------商品列表------------\n") # 商品列表 for index, product in enumerate(goods, 1): print("%s.%s %d" % (index, product['name'], product['price'])) print("\n-------------------------------")def select_shopping_history(): # 读取消费记录 with open(shopping_history_f_name, "r", encoding="utf-8") as shopping_history_f: print("\n---------您的消费记录----------\n") for line in shopping_history_f: shopping_history_list = line.strip().split('|') # print(shopping_history_list) _username = shopping_history_list[0].strip() _time = shopping_history_list[1].strip() _product = shopping_history_list[2].strip() if username in shopping_history_list: print("用户 {0} {1} 购买了 {2}".format(_username, _time, _product)) else: pass print("\n-------------------------------")def update_shopping_history(): # 更新消费记录 now_time = time.strftime('%Y-%m-%d %H:%M:%S') with open(shopping_history_f_name, "a", encoding="utf-8") as shopping_history_f: shopping_history_f.write("\n%s|%s|%s" % (username, now_time, goods[product_id - 1]['name']))# 商品信息goods = [ {
"name": "电脑", "price": 4000}, {
"name": "鼠标", "price": 200}, {
"name": "游艇", "price": 20000}, {
"name": "美女", "price": 1000}, {
"name": "T恤", "price": 50},]# 菜单栏choice_info = """【商品编号】购买商品【h】消费记录【m】余额查询【q】退出商城-------------------------------"""shopping_carts = [] # 初始购物车为空user_info_dict = {} # 初始化用户信息字典为空user_info_f_name = "user_info.txt" # 用户信息文件名user_info_f_temp_name = "user_info.txt.temp" # 用户信息临时文件名shopping_history_f_name = "shopping_history.txt" # 消费记录exit_flag = Falsecount = 0# 主程序开始select_user_info() # 读取用户信息文件,组成user_info_dict字典while count < 3 and not exit_flag: username = input('\n请输入用户名:') if username not in user_info_dict: count += 1 print("\n用户名错误") elif user_info_dict[username]['lock'] > 0: print("\n用户已被锁定,请联系管理员解锁后重新尝试") break else: while count < 3 and not exit_flag: password = input('\n请输入密码:') if password == user_info_dict[username]['password']: print("\n--------欢迎%s登陆本商城--------" % (username)) if int(user_info_dict[username]['money']) == 0: # money = 0表示是首次登陆的用户 while True: money = input("\n请输入您的工资:") # 工资只能是数字 if money.isdigit(): money = int(money) # print(money) break else: print("\n您的工资只能是数字") continue else: money = int(user_info_dict[username]['money']) print("\n\033[31;1m您上次购物后的余额为:%s 元!\033[0m\n" % (money)) while not exit_flag: product_list() # 打印商品列表 print(choice_info) # 选择信息 product_id = input("请输入您要的操作:") if product_id.isdigit(): product_id = int(product_id) if product_id >= 1 and product_id <= len(goods): if money >= goods[product_id - 1]['price']: money -= goods[product_id - 1]['price'] shopping_carts.append(goods[product_id - 1]['name']) print("\n\033[31;1m%s已购买成功!\033[0m\n" % (goods[product_id - 1]['name'])) update_shopping_history() # 写入消费记录文件 user_info_dict[username]['money'] = money update_user_info() # 更新工资余额到文件 else: print("\n\033[31;1m抱歉,%s购买失败!工资余额不足!\033[0m" % (goods[product_id - 1]['name'])) else: print("商品标号有误,请重新输入") elif product_id == "q": if len(shopping_carts) > 0: print("\n\033[31;1m您本次购买的商品及商品数量如下:\033[0m\n") shopping_carts_delRepeat = list(set(shopping_carts)) # 购物车列表去重 for index, product_carts in enumerate(shopping_carts_delRepeat, 1): print("%s. %s * %d" % ( index, product_carts, shopping_carts.count(product_carts))) # 显示同一商品数量 else: print("\n您本次没有购买东西!") print("\n\033[31;1m您的工资余额为:%s 元!\033[0m\n" % (money)) # user_info_dict[username]['money'] = money # update_user_info() # 更新工资余额到文件 exit_flag = True elif product_id == "h": select_shopping_history() choice_continue = input("\n回到菜单栏(直接按回车):") if choice_continue == 'y' or choice_continue == "Y" or choice_continue == "": continue else: print("\n操作失误,强制退出!") exit_flag = True elif product_id == "m": print("\n\033[31;1m您的工资余额为:%s 元!\033[0m\n" % (money)) # user_info_dict[username]['money'] = money # update_user_info() # 更新工资余额到文件 choice_continue = input("\n回到菜单栏(直接按回车):") if choice_continue == 'y' or choice_continue == "Y" or choice_continue == "": continue else: print("\n操作失误,强制退出!") exit_flag = True else: print("\n输入有误,请重新输入") else: count += 1 print('\n密码错误') continue if count >= 3: # 尝试次数大于等于3时锁定用户 if username == "": print("\n您输入的错误次数过多,且用户为空") elif username not in user_info_dict: print("\n您输入的错误次数过多,且用户 %s 不存在" % username) else: user_info_dict[username]['lock'] += 1 # 修改用户字典(锁定状态设为1) # print(user_info_dict) # 更新后的用户信息字典 update_user_info() # 更新user_info.txt文件内容 print("\n您输入的错误次数过多,%s 已经被锁定" % username)

 

---恢复内容结束---

转载于:https://www.cnblogs.com/newt/p/9042875.html

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